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date: Mon, 12 Dec 2005 03:09:26 -0800,
group: microsoft.public.platformsdk.telephony.tapi_3
back
Re: Bandwidth of telephony audio data
Hi Riley,
To (roughly) estimate storage size of raw audio wav files - you need to know
the sampling rate and the sampling 'size' or width. 8kHz means 8k times per
second. 8k*60 = 480k. If the sampling size is 8-bits then that means
480kb * 1.05 = 504kb per minute. (I am assuming roughly 5% overhead for file
descriptors and general "organizational" overhead and absolutely no
compression). If the sampling width is 16 bit, that would double the raw
data size, if 24 bit then triple the data size per minute.
This is far from offering precise measurements; most recording algorithms
incorporate some compression, but this should give you the tools to
calculate the raw data size.
Hope this helps!
Sincerely,
G
"Riley DeWiley" wrote in message
news:p9udnWQ5r731xwDeRVn-iQ@seanet.com...
> Sorry if this is a FAQ - if one wants to digitally sample the audio off a
> phone line and store it digitally in 'raw' form w/out significant loss,
> how much storage is needed for, say, one minute of conversation, before
> sophisticated compression like MP3 is applied?
>
> Basically I just need to know what 8kHz * 1 minute equals in bytes.
>
> An estimate is fine. So is a URL.
>
> Thanks.
>
> RDeW
>
date: Wed, 28 Dec 2005 06:03:45 -0800
author: News Guys gll2005
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