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date: Mon, 25 Feb 2008 06:50:17 -0800 (PST),
group: microsoft.public.xsl
back
Re: xslt (identity?) transformation
Thank you Martin!
Putting it all together:
------ snippet ---------
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="author"/>
<xsl:template match="author[@name = 'whatever_name_of_author]">
<xsl:copy>
<xsl:apply-templates select="@*"/> <-- I want the attributes
<xsl:apply-templates
select="book[NOT(contains(@title,'do_not_include_this_title))]"/>
</xsl:copy>
</xsl:template>
----- snippet ------
As I wanted to exclude the title I was searching for I've added the
not clause.
But one last thing - forgive me the stupid example with the books xml,
but my real world example is a bit more complex.
But for the sake of simplifying and sticking to the example:
What if I the books where nested and I wanted the "<xsl:apply-
templates
select="book[NOT(contains(@title,'do_not_include_this_title))]"/>"
to apply to all nested elements - no matter how deep they were
appearing under an author i still want to check the "title" attribute,
and if I find a book I do not like, discard it?
So - how do I shred away the <book title="title_212"/> from the XML
below when I do not know where in the structure it is , only that it
is below an author by a given name?
<author lastname="lastname_2" givenname="given_2">
<book title="title_21"/>
<book title="title_22"/>
<book title="title_211"/>
<book title="title_212"/>
<book title="title_23"/>
</author>
And again - thank you for taking the time to show me how this is done
- I've already learned a lot, and will keep digging :-)
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="author[@lastname != 'lastname_2']"/>
</xsl:stylesheet>
On 26 Feb, 14:24, Martin Honnen wrote:
> roger wrote:
> > if it possible to select all childelements of an "author" element -
> > EXCLUDING a few - based on the "title" attribute of the "book" element
> > in this example?
>
> Well you could write a template for author elements that processes only
> some book child elements e.g.
> <xsl:template match="author">
> <xsl:copy>
> <xsl:apply-templates select="@*"/>
> <xsl:apply-templates select="book[contains(@title,'foo')]> </xsl:copy>
> </xsl:template>
>
> --
>
> Martin Honnen --- MVP XML
> http://JavaScript.FAQTs.com/
date: Tue, 26 Feb 2008 12:55:03 -0800 (PST)
author: roger
Re: xslt (identity?) transformation
Never mind guys - I found a way to do it :-) Thanks again to both of
you for invaluable help! :-)
Best regards,
Roger
On 26 Feb, 21:55, roger wrote:
> Thank you Martin!
>
> Putting it all together:
>
> ------ snippet ---------
> <xsl:template match="@* | node()">
> <xsl:copy>
> <xsl:apply-templates select="@* | node()"/>
> </xsl:copy>
> </xsl:template>
>
> <xsl:template match="author"/>
>
> <xsl:template match="author[@name = 'whatever_name_of_author]">
> <xsl:copy>
> <xsl:apply-templates select="@*"/> <-- I want the attributes
> <xsl:apply-templates
> select="book[NOT(contains(@title,'do_not_include_this_title))]"/>
> </xsl:copy>
> </xsl:template>
> ----- snippet ------
>
> As I wanted to exclude the title I was searching for I've added the
> not clause.
>
> But one last thing - forgive me the stupid example with the books xml,
> but my real world example is a bit more complex.
> But for the sake of simplifying and sticking to the example:
> What if I the books where nested and I wanted the "<xsl:apply-
> templates
> select="book[NOT(contains(@title,'do_not_include_this_title))]"/>"
> to apply to all nested elements - no matter how deep they were
> appearing under an author i still want to check the "title" attribute,
> and if I find a book I do not like, discard it?
>
> So - how do I shred away the <book title="title_212"/> from the XML
> below when I do not know where in the structure it is , only that it
> is below an author by a given name?
>
> <author lastname="lastname_2" givenname="given_2">
> <book title="title_21"/>
> <book title="title_22"/>
> <book title="title_211"/>
> <book title="title_212"/>
> <book title="title_23"/>
> </author>
>
> And again - thank you for taking the time to show me how this is done
> - I've already learned a lot, and will keep digging :-)
>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
> <xsl:template match="@* | node()">
> <xsl:copy>
> <xsl:apply-templates select="@* | node()"/>
> </xsl:copy>
> </xsl:template>
>
> <xsl:template match="author[@lastname != 'lastname_2']"/>
>
> </xsl:stylesheet>
>
> On 26 Feb, 14:24, Martin Honnen wrote:
>
>
>
> > roger wrote:
> > > if it possible to select all childelements of an "author" element -
> > > EXCLUDING a few - based on the "title" attribute of the "book" element
> > > in this example?
>
> > Well you could write a template for author elements that processes only
> > some book child elements e.g.
> > <xsl:template match="author">
> > <xsl:copy>
> > <xsl:apply-templates select="@*"/>
> > <xsl:apply-templates select="book[contains(@title,'foo')]"/>
> > </xsl:copy>
> > </xsl:template>
>
> > --
>
> > Martin Honnen --- MVP XML
> > http://JavaScript.FAQTs.com/- Skjul sitert tekst -
>
> - Vis sitert tekst -
date: Wed, 27 Feb 2008 01:50:35 -0800 (PST)
author: roger
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