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date: Tue, 17 Jun 2008 10:05:01 -0700,    group: microsoft.public.exchange.admin        back       


Exchange 2007 problem - Dynamic distribution group filter   
Hi,

I've been having an issue with the custom filter for creating dynamic 
distribution group (DDG) via Exchange shell, particulary with the property 
"database" of the "recipientfilter" parameter. 

According to the MS documentation, property "database" accepts  the 
following three values: "mailbox database", "identity" and "distinguished 
name". I can only get results if using distinguished name, others give an 
error (see below).

Now distinguished name would be fine by me, as it's easily obtainable 
property of the database, however, once the DDG is created, my "distinguished 
name" which I specified in the command line is converted into "identity" 
value in the DDG object. 

In other words, my command goes somethign like this:


New-DynamicDistributionGroup -Name DynamicDG -OrganizationalUnit 
"something.com/Exchange Groups/Dynamic Distribution Groups" -Recipientfilter 
{((database -eq 'CN=DB2,CN=SG2,......CN=Configuration,DC=something,DC=com') 
-and (isresource -eq $false))}

Which works, and creates the DDG named DynamicDG. However, the Recipient 
filter property of this database shows as: 
"Exchange\StorageGroupXY\DatabaseXY". This is not distinguisned name - as 
I've entered above, it's "identity" of the database, which somehow got 
correctly translated, and it should still work, but it doesn't. And so the 
query fails when this DDG is called to work. Error says "The string 
"Exchange\StorageGroupXY\DatabaseXY" does not represent a valid distinguished 
name"

Any clues would be appreciated? How do I force distinguished name to stick, 
or identity to be accepted? Thanks.
date: Tue, 17 Jun 2008 10:05:01 -0700   author:   Sinisa T.

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