GINA replacement
Thu, 11 Mar 2010 12:52:53 -0000
Hi All,
Is it possible to have a replacement code for Microsoft GINA written on
.net?
Could somebody point me to a sample? The one I picked from MSDN does not
seem to work.
Thanks,
Kodjo
__________ Information from ESET NOD32 Antivirus, version of virus signature database 4798 (20100122) ________ ...
|
Service in Windows 2008 Server
Thu, 4 Mar 2010 18:50:01 -0800
I developed a windows service in .net 2 that runs perfectly on Windows XP
machines
This service reads a configuration XML file placed in the same directory as
the service (\Program Files\My Service\ConfigFile.xml)
When I installed it in Windows 2008 Server the service canâ??t read the file.
Iâ??ve tried chang ...
|
æ€æ¯’软件å…费下载 9796
Sun, 28 Feb 2010 17:34:01 -0800
许å¤?æ?§è?½é?®é¢?å??æ?¨ç??计ç®?æ?ºå®?å?¨é? æ? æ¶æ?ç??æ¯?ï¼?æ??好ç??å??æ³?对ä»?ï¼?è¿?æ?¯è¦å®?è£? é?²ç??æ¯?确认å??æ?¨ç??计ç®?æ?ºä¸?æ?´æ?°
æ?æ¯?软件å?è´¹ä¸?è½½ï¼?
http://antivirusfreecn.blogspot.com/
é?¾æ?¥ç½?ç«?ç??å??容ï¼?
http://antivirusfreecn.blogspot.com/
http://antivirusfreecn.blogspot.co ...
|
Logonuser function and domain
Thu, 18 Feb 2010 01:03:01 -0800
How can I use a domain account with a server inside the domain.
at the URL http://msdn.microsoft.com/en-us/library/aa378184(VS.85).aspx,it
is indicated that
lpszUsername [in]
A pointer to a null-terminated string that specifies the name of the user.
This is the name of the user account to log on to. If yo ...
|
LogonUser function
Wed, 17 Feb 2010 14:37:03 -0800
I am trying to access a server using LogonUser function as follows
Dim returnValue As Boolean = LogonUser(Domain\UserName, MachineName,
password, LOGON32_LOGON_NEW_CREDENTIALS, LOGON32_PROVIDER_DEFAULT,
tokenHandle)
I get a token, and seems to me that I get authenticated. However when I
execute the followi ...
|
TÃ?LÃ?CHARGEMENT GRATUIT ANTIVIRUS 5799
Fri, 12 Feb 2010 17:14:01 -0800
Nombreux problèmes de performance et la sécurité de votre ordinateur sont
causées par des virus malveillants, le meilleur moyen de lutter contre cela
est d'avoir
reconnu Antivirus installé et mis à jour sur votre ordinateur
Antivirus télécharger gratuitement à l'adresse:
http://antivirusfr.blogs ...
|
Getting error Security Authority cannot be contacted while using Kerberos
Thu, 11 Feb 2010 16:36:37 -0800
We have a server on which we are using Kerberos security. We have disabled
NTLM. When we try to access, we get the error 'Security Authority cannot be
contacted'.
We have created a virtual directory. Then we created an app pool. Then we
assigned a domain user to the pool. And added SPN entry for the server and ...
|
|
|
RE: Storing Secrets in Code
Mon, 1 Feb 2010 10:42:06 -0500
A long time ago, it was easy to tell application teams that they were not to
store secrets compiled into their code; as there were many people with the
skills necessary to dissassemble and decompile applications and retrieve
those secrets. Today, however, there are tools that seem to give people
false hop ...
|
Question on Certificate Chain
Thu, 28 Jan 2010 00:41:02 -0800
I have one question on certificate chain.
For example,
I have one URL: https://www.mycompony.com/validateCert.aspx.
The Certicate for this URL has below certicate path:
Root CA-> CA1 -> CA2 -> mycompony
I have make the Root CA trusted in my local computer.
When I want to use HttpWebRequest to access t ...
|
Key distribution in simetric algorithms
Wed, 27 Jan 2010 07:12:41 -0800 (PST)
Hi.
I am reading about criptography in .net and when it comes to simetric
algorithms, I could not understand exactly how to distribute the key.
My main doubt is, if I generate a key and a IV, do I need to
distribute both or only the key?
Regards,
Robert Scheer ...
|
